PhysicsCore22 min read

Physics of Solids

Crystal structure, deformation and why some materials conduct

This topic appears in:

01

How solids are put together

Solids divide into two kinds by how their particles are arranged. In a crystalline solid the atoms sit in a repeating three-dimensional pattern — a lattice — that continues in every direction. Metals, salt and diamond are crystalline.

In an amorphous solid there is no long-range order; the particles are arranged much as they were in the liquid, frozen in place. Glass, rubber and most plastics are amorphous.

The difference shows up in melting. A crystalline solid has one sharp melting point, because every bond is the same and they all break at the same temperature. An amorphous solid softens gradually over a range, which is precisely what lets glass be blown and shaped.

Most metals are polycrystalline: made of many small crystals, called grains, joined at boundaries in random orientations. Those grain boundaries matter — they get in the way of deformation, which is why a fine-grained metal is harder than a coarse-grained one.

CrystallineAmorphous
Arrangementregular, repeating latticeno long-range order
Meltingsharp melting pointsoftens over a range
Examplesmetals, salt, diamond, quartzglass, rubber, most plastics
02

Stress, strain and the Young modulus

Load a wire and it stretches. To compare materials rather than particular samples, the load is divided by the cross-sectional area to give stress, and the extension divided by the original length to give strain.

For small loads the two are proportional — Hooke's law — and the constant of proportionality is the Young modulus. It measures stiffness, and it belongs to the material: every steel wire has the same Young modulus regardless of its length or thickness.

Stress has the units of pressure, pascals. Strain has no units at all, being a length divided by a length. So the Young modulus is in pascals too, and for metals it runs to hundreds of gigapascals.

σ = F / Aε = e / LE = σ / εstrain is dimensionless; steel E ≈ 2 × 10¹¹ Pa, copper ≈ 1.2 × 10¹¹ Pa
σ
stressPa
ε
strain
E
Young modulusPa
e
extensionm
L
original lengthm

The gradient of the straight section is the Young modulus. Switch to glass and the plastic region vanishes entirely — it stays on the straight line until it shatters, which is what brittle means.

03

Elastic, plastic and brittle

Definition

Elastic limit — The greatest stress a material can take and still return to its original length once the load is removed.

Below the elastic limit, deformation is elastic: remove the load and the material springs back exactly. The atoms have been pulled slightly further apart but every one has stayed with its neighbours.

Past the elastic limit, deformation becomes plastic and is permanent. Whole planes of atoms have slipped over one another, and removing the load does not slide them back. This is what lets a metal be hammered into shape, drawn into wire, or bent and left bent.

A material with a long plastic region before breaking is ductile — copper is the standard example, which is why it becomes wire. One that breaks with almost no plastic region is brittle: glass, ceramics and cast iron all snap while still obeying Hooke's law.

Brittle is not the same as weak. Glass fibre is extremely strong in tension; it simply gives no warning before it fails, which is why brittle materials are avoided where a sudden failure would be dangerous.

Worked example 15 marks

A steel wire of length 3.0 m and diameter 1.2 mm is stretched by 2.1 mm under a load of 240 N. Calculate the Young modulus.

  1. Radius = 0.60 mm = 6.0 × 10⁻⁴ m.Halve the diameter first, then convert.
  2. A = πr² = π(6.0 × 10⁻⁴)² = 1.13 × 10⁻⁶ m².The squaring is where the powers of ten usually go wrong.
  3. σ = F/A = 240 / 1.13 × 10⁻⁶ = 2.12 × 10⁸ Pa.
  4. ε = e/L = 2.1 × 10⁻³ / 3.0 = 7.0 × 10⁻⁴.
  5. E = σ/ε = 2.12 × 10⁸ / 7.0 × 10⁻⁴ = 3.0 × 10¹¹ Pa.The right order of magnitude for steel.

≈ 3 × 10¹¹ Pa

Check the order of magnitude

For a metal, strain should come out very small — of order 10⁻³ or less — and the Young modulus around 10¹¹ Pa. A strain of 0.5 or a modulus of 10⁵ means a unit conversion has gone astray, almost always the area.

04

Why some solids conduct

In an isolated atom electrons occupy sharply defined energy levels. Bring 10²³ atoms together into a solid and those levels spread into broad bands of allowed energies, separated by gaps where no electron may sit.

Two bands matter. The valence band holds the bound electrons; the conduction band above it holds electrons free to move through the material. Whether a solid conducts comes down to the gap between them.

In a conductor the bands overlap, or the upper band is only part-filled. Electrons can move into free states with almost no energy, so current flows readily.

In an insulator the gap is large — several electronvolts. At ordinary temperatures essentially no electron has enough energy to cross it, so no current flows.

A semiconductor has a small gap, around one electronvolt. At absolute zero it is an insulator, but at room temperature a few electrons have enough thermal energy to jump the gap. Heat it and more make it across — which is exactly why a semiconductor's resistance falls as it warms, while a metal's rises.

Band gapAt room temperature
Conductornone — bands overlapconducts freely
Semiconductorsmall, ≈ 1 eVconducts a little; better when hot
Insulatorlarge, several eVdoes not conduct

Key points

  1. Crystalline solids have a repeating lattice and a sharp melting point; amorphous ones do not.
  2. E = σ/ε is a property of the material, not of the sample.
  3. Elastic deformation reverses; plastic deformation is permanent.
  4. Ductile means a long plastic region; brittle means almost none.
  5. Band gap decides conduction — none for a metal, small for a semiconductor, large for an insulator.

Practice questions

6 questions · 24 marks · full working on every one

Try each one on paper first, then open the working. The marks are shown where they are actually awarded, because that is where they are actually lost.

Short questions

3 · 6 marks

Two marks each, in the style of the short-question section of the paper. Answer in two or three lines.

SQ1[2 marks]
State two differences between a crystalline and an amorphous solid.
Model answer

A crystalline solid has a regular repeating lattice and a sharp melting point. An amorphous solid has no long-range order and softens over a range of temperature.

Examiner tip. Compare the same feature for both — arrangement, then melting behaviour.

SQ2[2 marks]
Explain the difference between elastic and plastic deformation in terms of atoms.
Model answer

In elastic deformation the atoms are pulled slightly further apart but keep the same neighbours, so the material returns to its original length. In plastic deformation planes of atoms slip permanently over one another, so it does not.

Examiner tip. The word "permanent" and the idea of planes slipping are what earn the marks.

SQ3[2 marks]
Explain why the resistance of a semiconductor falls as its temperature rises, while a metal's rises.
Model answer

In a semiconductor, thermal energy lifts more electrons across the small band gap into the conduction band, so there are more charge carriers. In a metal the number of carriers is fixed, and heating makes the ions vibrate more so the electrons collide with them more often.

Examiner tip. Two different mechanisms — more carriers versus more collisions. Both halves are needed.

Solved numericals

1 · 5 marks

Full working, one step per line, with the marks shown where they are awarded.

N1[5 marks]
A copper wire of length 2.0 m and cross-sectional area 3.5 × 10⁻⁷ m² stretches by 1.8 mm under a load of 38 N. Find the stress, the strain and the Young modulus.
Full working
  1. σ = F/A = 38 / 3.5 × 10⁻⁷[1]
  2. σ = 1.09 × 10⁸ Pa[1]
  3. ε = e/L = 1.8 × 10⁻³ / 2.0convert mm to m[1]
  4. ε = 9.0 × 10⁻⁴no units[1]
  5. E = σ/ε = 1.2 × 10¹¹ Paabout right for copper[1]

σ = 1.09 × 10⁸ Pa, ε = 9.0 × 10⁻⁴, E = 1.2 × 10¹¹ Pa

Examiner tip. A metal strain of 10⁻³ or less and a modulus near 10¹¹ Pa are the sanity checks worth applying.

Long questions

1 · 8 marks

Theory and numerical together, as they appear in the long-question section.

LQ1[8 marks]
A student stretches a copper wire and a glass fibre until each breaks, plotting stress against strain for both.
  1. Sketch and describe the shape of each graph. [4]
  2. Identify which material is ductile and which is brittle, giving a reason. [2]
  3. Explain what the gradient of the straight section represents. [2]
Mark scheme
  1. Copper: straight line at first, then curving over into a long plastic region before breaking[1]
  2. Copper reaches a maximum stress and then extends considerably before failure[1]
  3. Glass: straight line all the way[1]
  4. Glass breaks abruptly at the end of the straight line, with no plastic region[1]
  5. Copper is ductile — it has a long plastic region and can be drawn into wire[1]
  6. Glass is brittle — it breaks with almost no plastic deformation[1]
  7. The gradient is the Young modulus[1]
  8. It measures the stiffness of the material and is independent of the sample dimensions[1]

copper ductile with a long plastic region; glass brittle; gradient = Young modulus

Examiner tip. Brittle does not mean weak. Glass fibre is very strong in tension — it simply gives no warning before it fails.

Exam questions

1 · 5 marks

Multi-part questions with a full mark scheme.

Q1[5 marks]
Solids are classified as conductors, semiconductors or insulators by their band structure.
  1. Explain what is meant by a band gap. [2]
  2. Describe the band gap in each of the three classes. [3]
Mark scheme
  1. A range of energies that electrons in the solid are not allowed to have[1]
  2. It separates the valence band from the conduction band[1]
  3. Conductor: no gap — the bands overlap or the upper band is part-filled[1]
  4. Semiconductor: a small gap, about 1 eV, which some electrons cross at room temperature[1]
  5. Insulator: a large gap of several eV that electrons cannot cross at ordinary temperatures[1]

no gap / small gap / large gap

Examiner tip. The size of the gap is the whole classification. Quote rough numbers — about 1 eV against several — rather than only "small" and "large".