PhysicsCore24 min read

Special Theory of Relativity

Time dilation, length contraction and E = mc²

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01

Two postulates, and everything follows

Definition

Inertial frame — A frame of reference moving at constant velocity — not accelerating and not rotating.

Einstein built the whole of special relativity on two statements, both of which look harmless.

First, the laws of physics are the same in all inertial frames — in any laboratory moving at constant velocity. There is no experiment you can do inside a smoothly moving train that tells you it is moving. This idea was already old; Galileo knew it.

Second, the speed of light in a vacuum is the same for every observer, whatever their own motion or the motion of the source. This is the one that breaks everything.

Ordinarily speeds add. Throw a ball forward at 20 m/s from a train doing 30 m/s and the ground sees 50 m/s. The second postulate says light does not behave that way: shine a torch forward from a spaceship travelling at half the speed of light and both you and the observer outside measure the beam at exactly c.

Since speed is distance over time, and everybody must agree on the speed, they cannot all agree about distance and time. Something has to give — and what gives is the assumption that time and length are absolute.

The Michelson–Morley experiment

In 1887 Michelson and Morley tried to measure the Earth's motion through the supposed "aether" by comparing light speed along and across that motion. They found no difference whatsoever. The result was baffling until Einstein pointed out that it is exactly what the second postulate predicts.

02

Time dilation

A clock moving relative to you runs slow. Not because of anything mechanical — a moving clock of any kind, including a biological one, ticks more slowly as measured by you.

The factor is called gamma, and it depends only on speed. At everyday speeds gamma is so close to 1 that no effect is measurable. At 10% of light speed it is 1.005 — half a percent. At 99% of light speed it is 7.1.

The time measured in the frame where the two events happen at the same place is called the proper time. Every other observer measures a longer interval.

This is not a philosophical curiosity; it is measured routinely. Muons created high in the atmosphere have a half-life so short they should decay long before reaching the ground, yet they arrive in large numbers — because at 99.5% of light speed their internal clocks run about ten times slow. GPS satellites must correct for it too, and would drift by kilometres a day if they did not.

γ = 1 / √(1 − v²/c²)t = γ t₀t₀ is the proper time, measured where the events happen in the same place
γ
Lorentz factor
v
relative speedm s⁻¹
c
3.0 × 10⁸m s⁻¹
t₀
proper times
Worked example 15 marks

A spacecraft passes Earth at 0.80c. The crew measure a journey as taking 6.0 years. How long does it take as measured from Earth?

  1. The crew are present at both events, so 6.0 years is the proper time t₀.Identifying which time is proper is the crux of every question like this.
  2. γ = 1/√(1 − 0.80²) = 1/√(1 − 0.64).
  3. = 1/√0.36 = 1/0.60 = 1.67.
  4. t = γt₀ = 1.67 × 6.0.
  5. t = 10 years.Earth measures longer, always. If your answer is shorter, you have divided instead of multiplied.

10 years

Nothing happens until you are travelling very fast indeed. The curve is almost flat up to about half light speed, then climbs without limit as v approaches c — which is why relativity was never noticed in ordinary experience, and why nothing with mass can reach c.

03

Length contraction and relativistic mass

The same logic applied to distance gives length contraction: an object moving relative to you is measured shorter along its direction of motion, by the same factor gamma. Its dimensions across the motion are unaffected.

The two effects are two views of one situation. From the muon's own frame it does not live longer — the atmosphere is contracted, so it has less distance to travel. Both descriptions give the same answer, which is the point.

Mass also changes. As an object is accelerated its relativistic mass increases, and it takes ever more energy to gain each additional metre per second. As v approaches c the mass tends to infinity, so an infinite amount of energy would be needed to reach light speed. That is why nothing with mass can travel at c, and why particle accelerators need so much energy for so little extra speed.

Note carefully what each observer sees. The traveller notices nothing odd — their own clock, ruler and mass are perfectly normal. It is only measurements made of a system moving relative to you that change.

L = L₀ / γm = γ m₀L₀ and m₀ are the proper length and rest mass, measured in the object's own frame
L₀
proper lengthm
m₀
rest masskg
γ
Lorentz factor

Contraction is only along the motion

A spacecraft flying past at 0.9c is measured shorter front to back, but exactly the same height and width. Questions test this by asking about a dimension perpendicular to the motion — the answer there is "unchanged".

04

Mass–energy equivalence

The most famous consequence is that mass and energy are the same thing in different forms, related by E = mc². Because is about 9 × 10¹⁶, a very small mass corresponds to an enormous energy — one gram is worth roughly 9 × 10¹³ joules, comparable to a large power station running for a day.

This is not an exotic effect confined to bombs. Every energy change is a mass change. A stretched spring is very slightly more massive than a relaxed one; a hot cup of tea is more massive than a cold one. The differences are far too small to measure in those cases.

Where it does show up is in nuclear physics. The mass of a nucleus is always less than the total mass of its separate nucleons, and the difference — the mass defect — is the binding energy that holds it together, released when the nucleus formed.

Fusion in the Sun converts about four million tonnes of mass into energy every second, and that is what makes it shine. Fission in a reactor does the same on a smaller scale. In both cases nothing is destroyed: mass has simply been converted into an equivalent quantity of energy.

E = m c²ΔE = Δm c²E = γ m₀ c²the last form is the total energy of a moving body — rest energy plus kinetic energy
E
energyJ
m
masskg
c
3.0 × 10⁸m s⁻¹
Δm
mass defectkg
Worked example 24 marks

In a nuclear reaction the total mass decreases by 3.2 × 10⁻²⁸ kg. Calculate the energy released.

  1. Use ΔE = Δm c².
  2. ΔE = 3.2 × 10⁻²⁸ × (3.0 × 10⁸)².Square the speed of light — forgetting to is the standard slip.
  3. = 3.2 × 10⁻²⁸ × 9.0 × 10¹⁶.
  4. = 2.9 × 10⁻¹¹ J.Tiny in joules, but about 180 MeV — a typical nuclear energy.

2.9 × 10⁻¹¹ J

Key points

  1. The speed of light is the same for every observer — that is the postulate everything follows from.
  2. Moving clocks run slow by the factor γ; moving lengths contract by the same factor.
  3. Effects are negligible until speeds approach c.
  4. Nothing with mass can reach c, because its mass would become infinite.
  5. E = mc² — mass and energy are the same thing, and the mass defect is the binding energy.

Practice questions

6 questions · 24 marks · full working on every one

Try each one on paper first, then open the working. The marks are shown where they are actually awarded, because that is where they are actually lost.

Short questions

3 · 6 marks

Two marks each, in the style of the short-question section of the paper. Answer in two or three lines.

SQ1[2 marks]
State the two postulates of special relativity.
Model answer

The laws of physics are the same in all inertial frames. The speed of light in a vacuum is the same for all observers, regardless of the motion of the source or the observer.

Examiner tip. One mark each. The second is the one that produces every strange consequence.

SQ2[2 marks]
Explain why muons created in the upper atmosphere reach the ground when their half-life suggests they should not.
Model answer

They travel at close to the speed of light, so from our frame their internal clocks run slow and they survive far longer than their rest-frame half-life. Equivalently, in the muon's frame the atmosphere is length contracted, so there is less distance to cover.

Examiner tip. Either explanation earns the marks, but they must be consistent — do not mix the two frames.

SQ3[2 marks]
Explain why no object with mass can travel at the speed of light.
Model answer

Its relativistic mass is γm₀, and γ tends to infinity as v approaches c. An infinite amount of energy would therefore be needed to reach light speed.

Examiner tip. Name gamma and say it diverges. "Because Einstein said so" earns nothing.

Solved numericals

1 · 5 marks

Full working, one step per line, with the marks shown where they are awarded.

N1[5 marks]
A rod of proper length 2.0 m moves past an observer at 0.60c. Calculate the Lorentz factor and the length the observer measures. State its measured width if the rod is 0.10 m wide.
Full working
  1. γ = 1/√(1 − 0.60²) = 1/√0.64[1]
  2. γ = 1/0.80 = 1.25[1]
  3. Uses L = L₀/γdivide, because the moving object is shorter[1]
  4. L = 2.0/1.25 = 1.6 m[1]
  5. The width is unchanged at 0.10 m — contraction acts only along the direction of motion[1]

γ = 1.25, length 1.6 m, width still 0.10 m

Examiner tip. Length divides by gamma; time multiplies by it. Mixing those up reverses both answers.

Long questions

1 · 8 marks

Theory and numerical together, as they appear in the long-question section.

LQ1[8 marks]
A spacecraft travels to a star 8.0 light-years away at 0.80c, as measured from Earth.
  1. Calculate the Lorentz factor. [2]
  2. Calculate the journey time as measured from Earth. [2]
  3. Calculate the time experienced by the crew. [2]
  4. Explain, from the crew's point of view, why their journey took less time. [2]
Mark scheme
  1. γ = 1/√(1 − 0.64)[1]
  2. γ = 1.67[1]
  3. From Earth, t = distance/speed = 8.0/0.80light-years over fractions of c gives years[1]
  4. t = 10 years[1]
  5. Crew time = t/γ = 10/1.67the crew measure the proper time[1]
  6. = 6.0 years[1]
  7. In the crew's frame the distance is length contracted[1]
  8. It is only 8.0/1.67 = 4.8 light-years, and at 0.80c that takes 6.0 years — the two frames agree[1]

γ = 1.67; 10 years from Earth; 6.0 years for the crew

Examiner tip. The check in part (d) is worth doing every time: both frames must arrive at the same crew ageing, by different routes.

Exam questions

1 · 5 marks

Multi-part questions with a full mark scheme.

Q1[5 marks]
The Sun radiates energy at 3.8 × 10²⁶ W.
  1. Calculate the mass it converts to energy each second. [3]
  2. Explain what happens to this mass. [2]
Mark scheme
  1. Energy per second = 3.8 × 10²⁶ Ja watt is a joule per second[1]
  2. Rearranges E = mc² to m = E/c²[1]
  3. m = 3.8 × 10²⁶ / 9.0 × 10¹⁶ = 4.2 × 10⁹ kgabout four million tonnes every second[1]
  4. It is not destroyed — mass and energy are equivalent[1]
  5. In fusion the products have slightly less mass than the reactants, and that mass defect is radiated as energy[1]

4.2 × 10⁹ kg per second

Examiner tip. Say explicitly that nothing is destroyed. "The mass disappears" loses the conceptual mark.