Electrical power
Electrical power — The rate at which a component transfers energy, P = E/t. One watt is one joule per second.
Every coulomb passing through a component gives up V joules, and I coulombs pass every second. Multiply the two and you have the energy transferred per second, which is the power. That is the whole derivation of P = VI, and it is worth understanding rather than memorising, because the other two forms follow from it in one line each.
Substituting V = IR gives P = I²R. Substituting I = V/R gives P = V²/R. All three are the same statement; you choose whichever one matches the quantities the question gives you.
The I² form matters more than it looks. Because power loss depends on the square of the current, halving the current cuts the heating to a quarter. That single fact is why electricity is transmitted across the country at hundreds of thousands of volts.
- P
- powerW
- V
- potential differenceV
- I
- currentA
- R
- resistanceΩ
- E
- energyJ
A 2.0 kW electric kettle runs from the 230 V mains. Calculate the current it draws and the resistance of its element.
- Convert:
2.0 kW = 2000 W.Watts go with volts and amps; kilowatts belong with the kWh. - Rearrange
P = VItoI = P/V. I = 2000 / 230 = 8.7 A.R = V/I = 230 / 8.7 = 26 Ω.Or use P = V²/R directly, which gives the same value.
I = 8.7 A, R = 26 Ω
Change the supply voltage and watch the power reading. Doubling the voltage across a fixed resistance quadruples the power, because P = V²/R — the relationship is square, not proportional.
Paying for electricity: the kilowatt-hour
Kilowatt-hour — The energy transferred by a 1 kW appliance running for 1 hour. It is a unit of energy, not power, and equals 3.6 million joules.
The joule is far too small a unit for a household bill. A single kettle boiling uses about half a million of them. So energy suppliers bill in kilowatt-hours, and the arithmetic becomes easy: power in kilowatts, multiplied by time in hours, multiplied by the price per unit.
The name causes trouble because it sounds like a rate. It is not. A kilowatt is a rate; a kilowatt-hour is a rate multiplied by a time, which is a quantity of energy. Examiners ask you to state this, and "a unit of energy" is often a mark on its own.
The practical lesson from any bill is that it is the heating appliances that cost money. Anything designed to warm something — kettle, iron, immersion heater, air conditioner — runs at kilowatts. Anything designed to process information runs at watts. A phone charger left plugged in all year costs less than one hot bath.
A 2.0 kW heater is used for 3.0 hours a day. Electricity costs 22 rupees per kWh. Find the cost of running it for 30 days.
- Daily energy
= 2.0 × 3.0 = 6.0 kWh.Power already in kW, time already in hours — nothing to convert. - Monthly energy
= 6.0 × 30 = 180 kWh. - Cost
= 180 × 22. = 3960 rupees.- Sense check: one heater, one month, roughly four thousand rupees. Plausible for a 2 kW load.An answer in the tens or the millions would signal a conversion error.
3960 rupees
The three-pin plug and why each wire is there
Mains wiring in a plug is not arbitrary. Each of the three wires does one job, and exam questions almost always ask you to explain that job rather than recite a colour.
The live wire carries the alternating supply voltage and is the dangerous one. The neutral completes the circuit and sits at roughly earth potential. The earth wire normally carries no current at all: it is a safety path, connected to the metal case of the appliance.
If a fault lets the live wire touch a metal case, the case becomes live. Without an earth wire, the next person to touch it becomes the path to ground. With an earth wire, a very large current flows instantly to earth instead, which blows the fuse and disconnects the appliance before anyone touches it.
| Wire | Colour (international) | Job |
|---|---|---|
| Live | brown | carries the alternating supply voltage — the dangerous one |
| Neutral | blue | completes the circuit, near earth potential |
| Earth | green and yellow | safety path from the metal case to the ground |
The fuse goes in the live wire
A fuse must break the connection to the dangerous side of the supply. Put it in the neutral instead and it will still blow, but the appliance stays connected to the live wire and remains lethal to touch. Examiners award the mark for saying exactly that.
Fuses, circuit breakers and double insulation
A fuse is a deliberately weak link: a thin wire that melts when the current through it exceeds its rating, breaking the circuit. It is chosen to be just above the appliance's normal working current — near enough to react to a fault, far enough above to avoid blowing every time the appliance switches on.
Choosing a fuse is a two-step calculation that appears constantly. Work out the normal current from I = P/V, then pick the next standard fuse above it. The common ratings are 3 A, 5 A and 13 A.
A circuit breaker does the same job with an electromagnetic switch instead of a melting wire. It trips faster and, more usefully, can simply be reset instead of replaced.
Some appliances have no earth wire at all and are still safe. These are double insulated: the casing is plastic, and there is a second layer of insulation between the electrical parts and anything you can touch. With no metal case there is nothing to become live, so there is nothing to earth.
A 920 W hairdryer runs on 230 V. Calculate the normal operating current and state a suitable fuse.
I = P/V = 920 / 230.Both already in base units.I = 4.0 A.- The next standard rating above 4.0 A is 5 A.A 3 A fuse would blow in normal use; a 13 A fuse would allow a dangerous fault current before reacting.
4.0 A, so a 5 A fuse
Key points
- Fuse rating is chosen just above the normal working current.
- The fuse always goes in the live wire.
- A circuit breaker does the same job and can be reset.
- Double-insulated appliances need no earth wire because they have no metal case.
- Earth plus fuse is the pair that makes a metal-cased appliance safe.