Forget triangles for a moment
School teaches SOH-CAH-TOA first, and it works — for angles under 90°. But then you are asked for sin(210°) and the triangle story falls apart, because there is no triangle with a 210° angle.
The unit circle fixes this permanently. Draw a circle of radius 1. Sweep a line out from the centre at angle θ. Wherever the line meets the circle, that point's height is sin θ and its horizontal position is cos θ. That definition works for any angle at all, including negative ones and angles past 360°.
Press Play. The green sine wave on the right is literally the height of the rotating point, plotted against angle. The wave is not an analogy for the circle — it is the circle, unrolled.
Why sine goes negative
Between 180° and 360° the point on the circle sits below the centre. Its height is negative, so sin θ is negative. Nothing mysterious happened; the height simply went below zero.
The same reading explains why tan θ blows up at 90°. Since tan θ = sin θ / cos θ, and cos θ is the horizontal position, at 90° the point is directly above the centre — horizontal position 0 — and you are dividing by zero.
The identities worth memorising
| Identity | Where it comes from |
|---|---|
| sin²θ + cos²θ = 1 | Pythagoras on the radius-1 triangle |
| tan θ = sin θ / cos θ | Definition |
| sin(−θ) = −sin θ | Reflecting below the axis flips the height |
| cos(−θ) = cos θ | Reflecting keeps the horizontal position |
| sin(θ + 360°) = sin θ | A full lap returns you to the same point |
| sin(2θ) = 2 sin θ cos θ | Double-angle formula |
The first identity is free
The point on the unit circle is at (cos θ, sin θ), and it is exactly 1 unit from the centre. Pythagoras on that right triangle gives cos²θ + sin²θ = 1² immediately. You never need to memorise it — you can rebuild it in five seconds from the picture.
Radians, and why they exist
Degrees are arbitrary — the number 360 comes from ancient Babylonian astronomy, not from mathematics. Radians measure angle by arc length: an angle of 1 radian sweeps out an arc exactly 1 radius long.
This matters because calculus only behaves nicely in radians. The clean result d/dx sin x = cos x is true in radians and false in degrees (you would pick up an ugly factor of π/180).
The right-triangle ratios, which is where the paper starts
Before the unit circle, trigonometry is three ratios in a right-angled triangle. Label the sides relative to the angle you are working with: the hypotenuse is always opposite the right angle, the opposite is across from θ, and the adjacent is the remaining side touching θ.
The word "relative" is the whole difficulty. Move to the other acute angle of the same triangle and opposite and adjacent swap over, while the hypotenuse stays put.
The two sides used by the chosen ratio are highlighted. Change θ and watch which side is called "opposite" — it is decided by the angle you are standing at, never by the orientation of the page.
Angles of elevation and depression
These two words turn a height-and-distance problem into a right-angled triangle, and they are the standard application in the Punjab paper.
The angle of elevation is measured upward from the horizontal to your line of sight; the angle of depression is measured downward from the horizontal. Because the two horizontals are parallel, the angle of elevation from the bottom always equals the angle of depression from the top — which is how you transfer a given angle into the triangle you actually want.
From a point 40 m from the foot of a tower, the angle of elevation of the top is 55°. Find the height of the tower.
- Sketch the right-angled triangle: the tower is the opposite side, the 40 m is adjacent to the 55° angle.The sketch is what tells you which ratio to use; drawing it is worth the time.
- Opposite and adjacent together mean tan:
tan 55° = h / 40.The hypotenuse is neither given nor wanted, which rules out sine and cosine. h = 40 tan 55° = 40 × 1.428.h = 57.1m.Sensible: the angle exceeds 45°, so the height should exceed the 40 m base distance, and it does.
57.1 m
Add the observer's height if the question gives it
If the angle is measured from an instrument 1.5 m above the ground, your triangle gives the height above the instrument. The tower is 1.5 m taller than your answer. This final addition is a mark of its own and is the most commonly dropped mark in the whole topic.
Triangles that are not right-angled
SOH-CAH-TOA needs a right angle. When there is not one, two rules take over, and choosing between them is a matter of counting what you have been given.
Use the sine rule when you have a side opposite a known angle — that is, when the given information pairs a side with the angle facing it. Use the cosine rule when you have three sides, or two sides and the angle between them, because in those cases no such pair exists.
- a, b, c
- the three sideseach named after the angle opposite it
- A, B, C
- the three angles
- C in the area formula
- the angle between the two sides usedit must be the included angle
In triangle ABC, b = 8 cm, c = 5 cm and ∠A = 60°. Find a and the area.
- Two sides and the included angle, and no side-angle pair — so this is the cosine rule.Deciding which rule applies before substituting is what the first mark is for.
a² = 64 + 25 − 2(8)(5) cos 60° = 89 − 80(0.5) = 49.cos 60° = 0.5 exactly, which is why the examiner chose that angle.a = 7cm.Sensible: a lies between c and b + c, as any third side must.- Area
= ½(8)(5) sin 60° = 20 × 0.866 = 17.3 cm².The angle used must be the one between the two sides, which 60° is.
a = 7 cm; area ≈ 17.3 cm²
Set the calculator to degrees
A calculator left in radian mode gives answers that look plausible and are completely wrong. Check the mode indicator before the first calculation of every trigonometry question — and switch it back to radians for calculus.