MathematicsFoundation18 min read

Graphs in Practical Situations

What the gradient means, what the area means, and when neither means anything

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01

A graph of two real quantities

When a graph plots two measured quantities against each other, its features acquire physical meanings. Those meanings come entirely from the units, which is why the same shape says different things on different axes.

The gradient is the vertical unit divided by the horizontal unit. On a distance–time graph that is metres per second, a speed. On a speed–time graph it is metres per second per second, an acceleration. Reading the axes before interpreting anything is not a formality — it is the whole method.

GraphGradient meansArea under means
distance–timespeednothing useful
speed–timeaccelerationdistance travelled
cost–quantityprice per unitnothing useful
volume–timerate of flownothing useful
rate of flow–timechange in flow ratetotal volume

Switch between the two graphs with Gradient selected. A horizontal section means stopped on a distance–time graph and constant speed on a speed–time graph — the same shape, opposite meanings.

02

Distance–time graphs

Time runs along the horizontal axis and distance from the starting point up the vertical. The gradient is the speed, so a steeper line means faster.

Three shapes recur. A horizontal section means the distance is not changing — the object is stationary. A straight sloping section means constant speed. A curve means the speed is changing, getting steeper for speeding up and shallower for slowing down. A section sloping downward means returning towards the start.

The area under a distance–time graph means nothing

Multiplying metres by seconds gives metre-seconds, which is not a quantity anyone wants. Students trained on speed–time graphs sometimes calculate the area under a distance–time graph and present it as an answer. Ask what the units of the area would be before working it out — if they are meaningless, the area is too.

03

Speed–time graphs

Now the vertical axis is speed, so the gradient is the rate at which speed changes — the acceleration. A horizontal line no longer means stopped; it means moving at a constant speed. The object is only stationary where the graph touches zero.

And here the area does mean something: speed multiplied by time gives distance. The standard technique is to split the area into triangles and rectangles, find each, and add.

Worked example

A car accelerates from rest to 20 m/s in 10 s, holds that speed for 30 s, then decelerates to rest in 20 s. Find the acceleration, the total distance and the average speed.

  1. Acceleration = gradient of the first section = 20 ÷ 10 = 2 m/s².Change in speed divided by the time it took.
  2. First section is a triangle: ½ × 10 × 20 = 100 m.The area under a speed–time graph is the distance.
  3. Middle section is a rectangle: 30 × 20 = 600 m.
  4. Last section is a triangle: ½ × 20 × 20 = 200 m. Total = 900 m.Split into standard shapes rather than trying to find the whole area at once.
  5. Average speed = 900 ÷ 60 = 15 m/s.Total distance over total time — not the average of 0 and 20.

Acceleration 2 m/s²; distance 900 m; average speed 15 m/s

04

Conversion graphs and other practical graphs

A conversion graph is a straight line through the origin used to change between two units — kilometres and miles, rupees and dollars. Reading from either axis to the other converts in that direction, which makes it faster than arithmetic for repeated conversions and less accurate for any single one.

Other practical graphs follow the same principle. A water-filling graph of depth against time is steep where the container is narrow and shallow where it is wide, because the same volume raises the level less in a wider vessel. A graph of cost against quantity has a gradient equal to the unit price, and a vertical intercept equal to any fixed charge that applies regardless of quantity.

What a non-zero intercept tells you

A taxi fare graph that starts at Rs 200 when the distance is zero has a fixed charge of Rs 200 before any travelling. The gradient is then the rate per kilometre. Whenever a practical graph does not pass through the origin, the intercept is a standing cost or a starting value, and questions ask for its meaning in context rather than just its number.

Before you leave this chapter

  1. The gradient means vertical unit ÷ horizontal unit. Read the axes first.
  2. Distance–time: gradient is speed, horizontal means stopped, area means nothing.
  3. Speed–time: gradient is acceleration, horizontal means constant speed, area is distance.
  4. Find an area by splitting it into triangles and rectangles.
  5. A non-zero intercept on a practical graph is a fixed charge or a starting value.
05

Reading a graph back into a story

Half the marks in this topic come from describing a journey in words from its graph, or sketching a graph from a description. Both are done section by section: identify where the shape changes, then say what each section means in the language of the situation.

A good description names the quantity, the direction and the duration for every section — "travels away from home at a constant 40 km/h for 30 minutes", not "goes up".

Worked example

Describe the journey shown by a distance–time graph that rises steeply for 10 minutes, is horizontal for 5, rises gently for 20, then falls steeply to zero over 15 minutes.

  1. First section: distance increasing quickly — travelling away from the start at a high constant speed for 10 minutes.Straight and steep means constant and fast.
  2. Second section: horizontal, so the distance is unchanged — stationary for 5 minutes.Not "moving slowly" — the distance is not changing at all.
  3. Third section: rising gently — continuing away from the start but more slowly, for 20 minutes.A shallower gradient is a lower speed, in the same direction.
  4. Fourth section: falling to zero — returning all the way to the starting point in 15 minutes, faster than either outward stage.Downward means coming back; steepness gives the speed.

Out quickly, a five-minute stop, out again more slowly, then a fast return to the start.

Practice questions

6 questions · 20 marks · full working on every one

Try each one on paper first, then open the working. The marks are shown where they are actually awarded, because that is where they are actually lost.

Short questions

3 · 6 marks

Two marks each, in the style of the short-question section of the paper. Answer in two or three lines.

SQ1[2 marks]
What does a horizontal section represent on (i) a distance–time graph and (ii) a speed–time graph?
Model answer

(i) The object is stationary — its distance from the start is not changing. (ii) The object is moving at a constant speed — the speed is not changing, but it is still moving.

Examiner tip. This contrast is examined every year. The same shape means "stopped" on one graph and "steady" on the other.

SQ2[2 marks]
What does the area under a speed–time graph represent, and why?
Model answer

The distance travelled. Speed multiplied by time gives distance — metres per second times seconds gives metres — so the area, which is a product of the two axes, has the units of distance.

Examiner tip. Justify it from the units. That reasoning also tells you when an area is meaningless, as on a distance–time graph.

SQ3[2 marks]
A taxi fare graph crosses the vertical axis at Rs 150. Explain what this means.
Model answer

It is a fixed charge of Rs 150 applied before any distance is travelled — a flag-fall or booking fee. The gradient of the line then gives the additional cost per kilometre.

Examiner tip. Interpret the intercept in the context of the question. "The line starts at 150" describes the graph rather than explaining it.

Solved numericals

2 · 8 marks

Full working, one step per line, with the marks shown where they are awarded.

N1[4 marks]
A cyclist travels 6 km in 20 minutes, rests for 10 minutes, then returns to the start in 30 minutes. Describe the distance–time graph and calculate the speed of each moving stage in km/h.
Full working
  1. A straight line rising from (0, 0) to (20, 6)time in minutes on the horizontal axis[1]
  2. A horizontal section from (20, 6) to (30, 6) for the restdistance unchanged means stationary[1]
  3. Outward speed = 6 km ÷ (1/3) h = 18 km/h20 minutes is one third of an hour[1]
  4. A line falling from (30, 6) to (60, 0); return speed = 6 ÷ 0.5 = 12 km/hthe downward slope means returning towards the start[1]

Rise, horizontal, then fall to zero. Out at 18 km/h, back at 12 km/h.

Examiner tip. Convert minutes to hours before dividing, or the speeds come out sixty times too small. 20 minutes is 1/3 h, not 0.20 h.

N2[4 marks]
A train accelerates uniformly from rest to 30 m/s in 15 s, travels at that speed for 45 s, then decelerates uniformly to rest in 30 s. Find the total distance.
Full working
  1. Recognises that the distance is the area under the speed–time graphthis is the mark most often missed[1]
  2. Acceleration triangle: ½ × 15 × 30 = 225 m[1]
  3. Constant rectangle: 45 × 30 = 1350 m[1]
  4. Deceleration triangle: ½ × 30 × 30 = 450 m; total = 2025 m[1]

2025 m

Examiner tip. Sketch the shape and label the three pieces before calculating any of them. The alternative — one trapezium formula — works but is much easier to get wrong.

Long questions

1 · 6 marks

Theory and numerical together, as they appear in the long-question section.

LQ1[6 marks]
A tank is filled with water at a constant rate. The tank is a cylinder for its lower half and then widens into a cone shape above.
  1. Sketch the graph of water depth against time, describing its shape.
  2. Explain why the shape changes partway up.
  3. A second tank narrows towards the top. Describe how its graph would differ.
Mark scheme
  1. The first part is a straight line rising steadilyconstant cross-section means constant rate of rise[1]
  2. The second part is a curve that becomes progressively shallowerstill rising, but more slowly[1]
  3. The rate of water entering is constant, so equal volumes arrive in equal times[1]
  4. As the tank widens, that same volume spreads over a larger area and so raises the level by less — the depth increases more slowlythe explanation must connect area to rate of rise[1]
  5. A narrowing tank gives the opposite: the curve becomes progressively STEEPER[1]
  6. because the same volume is confined to a smaller area and therefore raises the level more[1]

(a) straight, then a flattening curve (b) a wider section spreads the same volume over more area (c) a narrowing tank steepens instead

Examiner tip. The rule for these: wider means shallower gradient. Sketch the container beside the graph and the shape follows directly from its width at each height.