MathematicsFoundation18 min read

Loci and Construction

Where a point can be, drawn with a straight edge and a pair of compasses

This topic appears in:

01

A locus is the answer to "where can it be?"

A locus (plural: loci) is the set of all points satisfying a stated condition. A goat tethered to a post by a 5 m rope can stand anywhere within 5 m of the post; the boundary of what it can reach is a circle of radius 5 m, and that circle is the locus of points exactly 5 m from the post.

Every locus question is answered by asking two things: what condition must the point satisfy, and what shape is made by all the points that satisfy it. There are only four standard answers at this level, and every complicated question is a combination of them.

ConditionLocusHow to construct it
A fixed distance r from a point Aa circle, centre A, radius rcompasses set to r
Equidistant from two points A and Bthe perpendicular bisector of ABequal arcs from A and from B
A fixed distance d from a linetwo parallel lines, one each sidemeasure d at two places on each side
Equidistant from two intersecting linesthe bisector of the angle between themarc across both arms, then equal arcs

Look at d from a line: there are two parallel lines, not one. Drawing only the one above the line is the commonest way to lose a mark in this chapter.

02

Constructions, and why the arcs must stay

A construction is done with straight edge and compasses only — no protractor and no measuring with a ruler, unless the question says otherwise. The marks are given for the construction arcs, so leaving them on the page is not untidiness, it is the evidence.

These are the constructions the syllabus expects, and each is worth practising until it takes under a minute.

  • Perpendicular bisector of AB — arcs of the same radius (more than half of AB) from A and from B, above and below; join the two crossings.
  • Bisector of an angle — an arc from the vertex cutting both arms, then equal arcs from those two points; join the vertex to their crossing.
  • Perpendicular from a point to a line — an arc from the point cutting the line twice, then bisect the segment between those two cuts.
  • Angles of 60° and 90° — 60° from an equilateral triangle construction; 90° from a perpendicular; bisect either to get 30° or 45°.
  • Triangles from SSS, SAS or ASA data, and the circumcircle or incircle of a triangle.

Do not erase your working

A perfectly accurate perpendicular bisector drawn with a protractor scores zero in a construction question. The mark is for the pair of arcs, not for the line. Keep them visible, keep the compass radius unchanged when the method requires it, and use a sharp pencil so the crossings are single points.

03

Regions, and combining two conditions

Questions rarely stop at one condition. "Shade the region that is less than 4 cm from A and nearer to B than to C" needs two loci drawn and then the overlap identified.

The method is mechanical. Draw the boundary for each condition as a line or an arc. Decide which side of each boundary satisfies its condition — a quick test with any convenient point settles it. Then shade only where all the conditions are met.

Worked example

A and B are 6 cm apart. Shade the region that is within 4 cm of A and nearer to B than to A.

  1. Draw a circle of radius 4 cm centred on A. The first condition is satisfied inside it."Within" means the interior, and the boundary itself is usually included unless the question says "less than".
  2. Construct the perpendicular bisector of AB with arcs from A and from B.Nearer to B than to A is decided by the perpendicular bisector — every point on it is equidistant from the two.
  3. Test which side is nearer to B: pick B itself, which is obviously nearer to B, so the required side is the one containing B.Testing with a convenient point is faster and safer than reasoning about which side is which.
  4. Shade the part of the circle lying on B's side of the bisector.The answer is the overlap of the two regions, not their union.

The lens-shaped region inside the circle and on B's side of the perpendicular bisector of AB.

Before you leave this chapter

  1. Fixed distance from a point → circle. Equidistant from two points → perpendicular bisector.
  2. Fixed distance from a line → two parallel lines, one on each side.
  3. Equidistant from two lines → the angle bisector.
  4. Construction arcs are the marks. Never rub them out, and never use a protractor unless invited to.
  5. For a region, draw each boundary, test which side satisfies the condition, and shade only the overlap.
05

The contexts these questions actually arrive in

Loci questions are almost never phrased in the language of the chapter. They arrive as a story, and the first task is to translate each sentence into one of the four standard conditions.

The question saysIt meansDraw
a goat tied by a 5 m ropeat most 5 m from the posta circle, shade inside
equally far from two lighthousesequidistant from two pointsperpendicular bisector
at least 20 m from the motorwaya fixed distance from a linetwo parallel lines
inside the angle between two walls, equally far from eachequidistant from two linesthe angle bisector
nearer to A than to Ba region, not a linethe bisector, then shade A's side

Watch for an obstruction

A goat tied to the corner of a shed does not sweep a full circle: the building blocks part of it, so the region is three quarters of a circle, and if the rope is longer than a wall the animal wraps round the corner with a shorter radius. Reading the question for what blocks the path is worth more than any construction skill.

Practice questions

6 questions · 20 marks · full working on every one

Try each one on paper first, then open the working. The marks are shown where they are actually awarded, because that is where they are actually lost.

Short questions

3 · 6 marks

Two marks each, in the style of the short-question section of the paper. Answer in two or three lines.

SQ1[2 marks]
Define a locus and give one everyday example.
Model answer

A locus is the set of all points that satisfy a given condition. Example: the locus of points 5 m from a fixed post is a circle of radius 5 m centred on the post — the path traced by a goat at the end of a taut 5 m rope.

Examiner tip. The phrase "set of all points" is the mark. A description of one example without the general definition scores half.

SQ2[2 marks]
State the locus of points equidistant from two fixed points A and B, and say how it is constructed.
Model answer

The perpendicular bisector of AB. Construct it by drawing arcs of equal radius (greater than half AB) from A and from B, above and below the line, and joining the two intersections.

Examiner tip. The construction detail is worth the second mark. Mentioning that the radius must exceed half of AB shows you know why the arcs meet at all.

SQ3[2 marks]
Why must construction arcs be left visible in a geometry answer?
Model answer

The marks in a construction question are awarded for the method, which is shown by the arcs. A line drawn accurately by measurement, with no arcs, earns no marks even if it is in exactly the right place.

Examiner tip. This is a "state the rule" question. Answer it in one sentence and move on.

Solved numericals

2 · 8 marks

Full working, one step per line, with the marks shown where they are awarded.

N1[4 marks]
Construct triangle ABC in which AB = 7 cm, BC = 5 cm and AC = 6 cm. Then construct the perpendicular bisector of AB.
Full working
  1. Draws AB = 7 cm accurately as the basestart with the longest side; it makes the arcs easier to cross[1]
  2. Arc of radius 6 cm from A and arc of radius 5 cm from B, crossing at Cboth arcs must be visible[1]
  3. Completes triangle ABC with straight lineswithin 2 mm tolerance[1]
  4. Perpendicular bisector of AB drawn with arcs from A and from B of equal radiusthe bisector must pass through the midpoint at right angles[1]

Triangle constructed by SSS, with the bisector of AB drawn using equal arcs from A and B.

Examiner tip. Set the compass from the ruler each time rather than estimating. An arc drawn at 5.6 cm instead of 6 cm puts C out of tolerance and costs the mark for the triangle.

N2[4 marks]
Two towns P and Q are 8 km apart. A radio mast is to be built less than 6 km from P and nearer to Q than to P. Describe and construct the region in which it can be built.
Full working
  1. Circle centred P with radius 6 km, and the required region is inside itscale drawing, e.g. 1 cm to 1 km[1]
  2. Perpendicular bisector of PQ constructed with arcs[1]
  3. Identifies the side of the bisector containing Q as "nearer to Q"[1]
  4. Shades the overlap: inside the circle and on Q's side of the bisectorshading the union instead of the intersection loses this mark[1]

The region inside the 6 km circle about P and on Q's side of the perpendicular bisector of PQ.

Examiner tip. State your scale before you draw anything. An unlabelled scale drawing can lose marks even when the geometry is perfect.

Long questions

1 · 6 marks

Theory and numerical together, as they appear in the long-question section.

LQ1[6 marks]
A rectangular garden ABCD has AB = 10 m and BC = 6 m. A tree is to be planted so that it is at least 3 m from the wall AB and equidistant from the corners A and D.
  1. Describe the locus of points at least 3 m from AB.
  2. Describe the locus of points equidistant from A and D.
  3. Explain how the two loci combine to locate the possible positions of the tree.
Mark scheme
  1. A line parallel to AB at a distance of 3 m from itinside the garden only, since the tree must be in the garden[1]
  2. The required region is on the far side of that line from AB"at least" makes this a region, not just a line[1]
  3. The perpendicular bisector of AD[1]
  4. Which, since AD is a side of the rectangle, runs parallel to AB through the midpoint of AD[1]
  5. The tree lies where the bisector meets the allowed region[1]
  6. That is the part of the perpendicular bisector of AD that is 3 m or more from AB, i.e. a segment of it inside the gardenaccept a clearly drawn and labelled answer[1]

(a) a parallel line 3 m from AB, with the region beyond it (b) the perpendicular bisector of AD (c) the part of the bisector lying at least 3 m from AB

Examiner tip. When one condition gives a region and the other gives a line, the answer is part of that line, not a point. Read carefully whether the question wants a point, a line or a region.