MathematicsFoundation20 min read

Fractions, Decimals and Percentages

Three ways of writing the same thing, and the reverse percentage everybody gets wrong

This topic appears in:

01

One quantity, three notations

A fraction, a decimal and a percentage are three ways of writing the same proportion, and moving between them freely is what makes the rest of this chapter easy.

A fraction becomes a decimal by dividing. A decimal becomes a percentage by multiplying by 100. A percentage becomes a fraction by writing it over 100 and cancelling. The conversions worth knowing by sight are the common ones, because recognising them saves working every time.

FractionDecimalPercentage
1/20.550%
1/40.2525%
3/40.7575%
1/50.220%
1/30.333…33⅓%
1/80.12512.5%
2/30.666…66⅔%

Which form to work in

For calculating, decimals are usually easiest — a calculator handles them directly. For exact answers, fractions are better, since 1/3 is exact and 0.333 is not. For comparing, percentages win, because everything is out of the same 100. Choosing the right form for the job is half the skill.

02

Percentage of, increase and decrease

Finding a percentage of an amount is a multiplication: 15% of 240 is 0.15 × 240 = 36. The word "of" means multiply, and converting the percentage to a decimal first is quicker than any other route.

For an increase or decrease, the efficient method is a single multiplier rather than finding the change and then adding it. An increase of 15% multiplies by 1.15; a decrease of 15% multiplies by 0.85. One step instead of two, and far fewer errors.

percentage of an amount:(P/100) × amountincrease by P%:× (1 + P/100)decrease by P%:× (1 − P/100)percentage change:(change ÷ ORIGINAL) × 100the denominator of a percentage change is always the ORIGINAL value, never the new one
Worked example

A shirt costing Rs 1200 is reduced by 15%, then the reduced price is increased by 15%. Is the final price Rs 1200?

  1. Decrease: multiply by 0.85, giving 1200 × 0.85 = 1020.One multiplier does the whole decrease.
  2. Increase: multiply by 1.15, giving 1020 × 1.15 = 1173.The 15% is now 15% of 1020, not of 1200 — that is the whole point.
  3. The final price is Rs 1173, not Rs 1200.A 15% rise does not undo a 15% fall, because the two percentages are of different amounts.
  4. Combined multiplier: 0.85 × 1.15 = 0.9775, a net fall of 2.25%.Multipliers can be combined directly, which is why they are worth using.

No — Rs 1173. A percentage increase and decrease of the same size do not cancel.

03

Reverse percentages

This is the topic that separates grades, and it is one idea: when you are told the price after a change, that price is not 100%.

If a price includes 20% tax, the amount you see is 120% of the original. Dividing by 1.2 recovers the original. The near-universal error is to take 20% off the final price instead, which gives a different and wrong answer — because 20% of the larger figure is more than 20% of the smaller one.

Worked example

After a 12% increase, a salary is Rs 44 800. What was it before?

  1. The new salary is 112% of the old one, so the multiplier used was 1.12.Write down what the given figure represents as a percentage. This one step is the whole question.
  2. To undo a multiplication, divide: 44 800 ÷ 1.12.Not subtract 12% — that would be taking 12% of the wrong number.
  3. = 40 000.
  4. Check: 40 000 × 1.12 = 44 800Always check forwards. The wrong method would have given 39 424, which fails this check immediately.

Rs 40 000

How to spot a reverse percentage question

Look for the word after, or a price described as including tax, or the phrase "in a sale". If the figure you are given is the one that has already been changed, you must divide by the multiplier. If it is the one before the change, you multiply. Deciding which of the two you have been given is the entire question.

04

Simple and compound interest

Simple interest is calculated on the original amount every time, so the same interest is added each year and the total grows in a straight line.

Compound interest is calculated on the amount currently there, so each year's interest is slightly larger than the last and the total grows exponentially. Nearly all real savings and loans are compound, and the difference over a long period is substantial.

simple interestI = (P × R × T) / 100compound amountA = P (1 + R/100)ᵀcompound interest = A − Pthe compound formula gives the TOTAL amount, so subtract the principal to get the interest alone
P
the principal — the amount invested or borrowed
R
the rate per period, as a percentage
T
the number of periodsusually years

Before you leave this chapter

  1. Fraction → decimal by dividing; decimal → percentage by multiplying by 100.
  2. Use a single multiplier: increase by 15% is × 1.15, decrease is × 0.85.
  3. Percentage change divides by the ORIGINAL value.
  4. Told the amount AFTER a change? Divide by the multiplier — never subtract the percentage.
  5. Simple interest is on the principal each time; compound is on the running total.
05

Seeing the three forms as one quantity

Converting between fractions, decimals and percentages becomes automatic once you stop thinking of them as three different things. They are three notations for the same amount, and a bar divided into equal parts shows all three at once.

Choose 1/3 and look at the decimal. It never terminates, so any decimal written down is an approximation — which is exactly why an exact answer must be left as a fraction.

Rounding early destroys accuracy

Working with 0.33 instead of 1/3 introduces an error that grows with every subsequent operation. In a multi-step calculation, keep fractions or full calculator accuracy throughout and round only the final answer. Rounding at each stage is one of the few ways to lose marks while doing every step correctly.

Practice questions

6 questions · 20 marks · full working on every one

Try each one on paper first, then open the working. The marks are shown where they are actually awarded, because that is where they are actually lost.

Short questions

3 · 6 marks

Two marks each, in the style of the short-question section of the paper. Answer in two or three lines.

SQ1[2 marks]
Increase 350 by 24%.
Model answer

Multiply by 1.24: 350 × 1.24 = 434.

Examiner tip. One multiplier beats finding 24% and adding it. Fewer steps means fewer places to go wrong, and it is faster.

SQ2[2 marks]
A price falls from Rs 80 to Rs 68. Calculate the percentage decrease.
Model answer

Change = 12. Percentage change = (12 ÷ 80) × 100 = 15%, dividing by the original price.

Examiner tip. The denominator is the original, 80. Dividing by 68 gives 17.6% and is the standard error.

SQ3[2 marks]
Write 0.375 as a fraction in its lowest terms and as a percentage.
Model answer

0.375 = 375/1000 = 3/8, and 0.375 × 100 = 37.5%.

Examiner tip. Cancel by dividing top and bottom by 125. Recognising 0.375 as 3/8 by sight is worth memorising.

Solved numericals

2 · 8 marks

Full working, one step per line, with the marks shown where they are awarded.

N1[4 marks]
A car costs Rs 1 495 000 including 15% sales tax. Calculate the price before tax.
Full working
  1. The stated price is 115% of the pre-tax priceidentifying this is the key step[1]
  2. So divide by the multiplier: 1 495 000 ÷ 1.15not subtract 15%[1]
  3. = Rs 1 300 000[1]
  4. Check: 1 300 000 × 1.15 = 1 495 000a verification is expected in reverse percentage questions[1]

Rs 1 300 000

Examiner tip. Subtracting 15% would give Rs 1 270 750, which fails the check. Always verify forwards — it takes one line and catches the wrong method every time.

N2[4 marks]
Rs 50 000 is invested at 8% per year compound interest. Find the amount after 3 years and the interest earned.
Full working
  1. Uses A = P(1 + R/100)ᵀ with P = 50 000, R = 8, T = 3[1]
  2. A = 50 000 × 1.08³the multiplier raised to the power of the years[1]
  3. = 50 000 × 1.259712 = Rs 62 985.60[1]
  4. Interest = 62 985.60 − 50 000 = Rs 12 985.60the formula gives the total, so the principal must be subtracted[1]

Amount Rs 62 985.60; interest Rs 12 985.60

Examiner tip. Simple interest would have given Rs 12 000. The extra Rs 985.60 is the interest earned on interest, and the gap widens every year.

Long questions

1 · 6 marks

Theory and numerical together, as they appear in the long-question section.

LQ1[6 marks]
A shop buys a phone for Rs 30 000 and marks it up by 40%. In a sale the marked price is reduced by 25%.
  1. Calculate the marked price.
  2. Calculate the sale price.
  3. Calculate the shop's percentage profit on the sale price, and comment on whether a 40% markup followed by a 25% discount returns to the cost price.
Mark scheme
  1. Marked price = 30 000 × 1.40[1]
  2. = Rs 42 000[1]
  3. Sale price = 42 000 × 0.75a 25% reduction is a multiplier of 0.75[1]
  4. = Rs 31 500[1]
  5. Profit = 1500, so percentage profit = (1500 ÷ 30 000) × 100 = 5%divided by the cost price, the original[1]
  6. No — the combined multiplier is 1.40 × 0.75 = 1.05, a net 5% gain, because the 25% is taken from the larger marked price rather than from the costthe explanation is the mark[1]

(a) Rs 42 000 (b) Rs 31 500 (c) 5% profit — the percentages act on different amounts

Examiner tip. The combined multiplier 1.40 × 0.75 = 1.05 answers the whole of part (c) in one line, and shows why the two percentages do not cancel.