MathematicsCore22 min read

Circular Measure

The angle unit that makes arc length and sector area almost trivial

This topic appears in:

01

Why degrees are the awkward unit

Definition

Radian — The angle subtended at the centre of a circle by an arc whose length equals the radius.

There is nothing natural about 360. It reaches us from Babylonian astronomy, where a year was counted as roughly 360 days, and it survives because it divides neatly by so many numbers. It is a convention, and a useful one for navigation and for drawing.

It is a poor unit for mathematics, though, because it has no relationship to the circle it measures. Ask for the length of an arc in degrees and you must first work out what fraction of the full turn you have, then multiply by the full circumference. Two steps, and a fraction to keep track of.

Radians remove that step by defining the angle in terms of the circle itself.

02

One radian, and why it has no unit

Take a circle, take a piece of string exactly as long as the radius, and bend it round the rim. The angle between the two radii at the ends of that string is one radian. That is the whole definition — no constants, no conversion factor, just a comparison of a curved length against a straight one.

Because a radian is one length divided by another, the units cancel. This is why an angle in radians is a pure number, and why sin θ is happy to accept it while sin 30° quietly needs a degree symbol to be meaningful. It also explains something that confuses people later: in s = rθ the θ contributes no unit at all, so a length times a pure number gives a length, exactly as it should.

Start on One radian: the thick arc is exactly as long as the radius. Then switch to Arc length and Sector area and drag θ — both quantities are just the angle with something multiplied onto it.

03

Converting, and the values worth knowing cold

A full turn is a circumference of 2πr wrapped onto a radius r, so it is 2π radians. That single fact generates every conversion you will ever need.

DegreesRadiansWhere it turns up
30°π/6the 1, 2, √3 triangle
45°π/4the isosceles right triangle
60°π/3the equilateral triangle
90°π/2quarter turn, one asymptote of tan
180°πhalf turn
360°full turn
2π rad = 360°π rad = 180°1 rad = 180/π ≈ 57.296°degrees → radians: × π/180radians → degrees: × 180/πmultiply by π/180 going in, by 180/π coming out
rad
radiansa ratio of two lengths, so it carries no unit
°
degrees360 to a full turn, purely by convention
× π/180
degrees → radians
× 180/π
radians → degreesthe same fraction, inverted

Set the calculator, then check it

Almost every lost mark in this topic is a calculator left in the wrong mode. Before starting, type sin 1. If the answer is 0.841 you are in radians; if it is 0.0175 you are in degrees. Do this check at the start of the paper, not after an answer looks strange — by then you may have carried the error through several parts.

04

Arc length

The full circumference 2πr corresponds to the full angle 2π. Arc length is therefore directly proportional to angle, and the constant of proportionality is simply r.

That proportionality is the entire derivation. An angle θ is the fraction θ/2π of a full turn, so the arc is that fraction of 2πr — and the 2π cancels.

s = rθ(θ in radians)arc length = radius × angle
s
arc lengthmeasured along the curve, not across it
r
radius
θ
angle at the centrein radians, always
Worked example

A circle has radius 8 cm. Find the length of the arc subtending an angle of 0.75 radians at the centre.

  1. Check the angle is in radians. It is — the question says so, and there is no degree symbol.The formula is only valid in radians. If the angle had been given in degrees it would need converting first.
  2. s = rθ = 8 × 0.75Straight substitution; no fraction of a turn to work out.
  3. s = 6 cmThe unit is centimetres because θ contributed no unit — a length times a pure number is a length.

s = 6 cm

05

Sector area

The same proportional argument works for area. A sector is the fraction θ/2π of the disc, and the disc has area πr², so the sector has area (θ/2π) × πr². The π and the 2 tidy up into the standard result.

A = ½r²θ(θ in radians)check: θ = 2π → A = ½r²(2π) = πr²sector area = half the radius squared, times the angle
A
area of the sectortwo radii and an arc — the pizza slice
r
radius
θ
angle at the centrein radians; θ = 2π must return πr²

A useful way to remember it

Sector area is ½ × arc × radius, since ½ × (rθ) × r = ½r²θ. That is the circular version of ½ × base × height for a triangle, which is not a coincidence — a very thin sector is very nearly a triangle with base and height r.

06

Segments, and the subtraction that defines them

A sector is bounded by two radii and an arc — the slice of pizza. A segment is bounded by a chord and an arc — the slice with the crust, once the triangular part has been cut away.

There is no separate formula worth memorising. A segment is a sector minus the triangle formed by the two radii and the chord, and that triangle has area ½r² sin θ by the ½ab sin C rule, since both enclosing sides are radii.

segment = sector − triangleA = ½r²θ − ½r² sin θ = ½r²(θ − sin θ)the triangle uses ½ab sin C with a = b = r
½r²θ
the sectorbounded by two radii and the arc
½r² sin θ
the triangletwo radii and the chord, by ½ab sin C
θ
angle at the centrein radians throughout, including inside the sine

The three area results together

  1. Sector: ½r²θ — two radii and an arc.
  2. Triangle: ½r² sin θ — two radii and the chord.
  3. Segment: ½r²(θ − sin θ) — the difference between them.
  4. Perimeter of a sector is 2r + rθ: do not forget the two straight sides.
  5. Perimeter of a segment is rθ + 2r sin(θ/2): the arc plus the chord.
07

Where the marks are actually lost

The mathematics in this topic is short, so examiners test it through the setting up rather than the calculation. Four errors account for most of the lost marks.

  • Calculator in the wrong mode. Everything downstream is then wrong, and the working looks perfectly correct.
  • Using a degree angle in a radian formula. s = rθ with θ = 60 rather than π/3 gives an arc nearly sixty times too long. A sanity check helps: an arc cannot exceed the circumference.
  • Confusing perimeter with arc length. "Find the perimeter of the sector" wants rθ + 2r. Answering alone is the single most common slip in the topic.
  • Forgetting that the sine also takes radians. In ½r²(θ − sin θ) the θ inside the sine is the same radian value, not a degree conversion.

Read what is being asked for

Area or perimeter? Sector or segment? These questions are worth few marks each and are designed so that the arithmetic is easy — which means the mark is genuinely for identifying the right region. Sketch it and shade the part you want before writing anything down.

Practice questions

5 questions · 17 marks · full working on every one

Try each one on paper first, then open the working. The marks are shown where they are actually awarded, because that is where they are actually lost.

Short questions

2 · 4 marks

Two marks each, in the style of the short-question section of the paper. Answer in two or three lines.

SQ1[2 marks]
Define a radian, and explain why an angle measured in radians has no units.
Model answer

A radian is the angle subtended at the centre of a circle by an arc equal in length to the radius. It has no units because it is a length divided by a length, so the units cancel.

Examiner tip. Two marks, two parts — the definition and the reason. Say "arc equal to the radius", not just "arc and radius".

SQ2[2 marks]
Explain why the formula A = ½r²θ gives the area of the whole circle when θ = 2π.
Model answer

Substituting θ = 2π gives A = ½r²(2π) = πr², the standard area of a circle. This works because 2π radians is a complete turn, so the sector becomes the entire disc.

Examiner tip. A "show that" in disguise — do the substitution explicitly rather than asserting the result.

Solved numericals

2 · 7 marks

Full working, one step per line, with the marks shown where they are awarded.

N1[3 marks]
A sector of a circle of radius 12 cm has an angle of 0.6 radians at the centre. Find (a) the arc length, (b) the perimeter of the sector.
Full working
  1. s = rθ = 12 × 0.6 = 7.2 cmDirect substitution into the arc length formula.[1]
  2. Perimeter = arc + two radii = 7.2 + 12 + 12The sector is bounded by the arc and both straight radii.[1]
  3. Perimeter = 31.2 cmA perimeter is a length, so the unit stays centimetres.[1]

Arc 7.2 cm; perimeter 31.2 cm

N2[4 marks]
A circle has radius 10 cm. A chord subtends an angle of 1.4 radians at the centre. Find the area of the minor segment cut off by the chord, giving your answer to 3 significant figures.
Full working
  1. Sector area = ½r²θ = ½ × 100 × 1.4 = 70 cm²The sector containing the segment.[1]
  2. Triangle area = ½r² sin θ = ½ × 100 × sin 1.4Two sides are radii and the included angle is θ, so ½ab sin C applies with a = b = r.[1]
  3. = 50 × 0.98545 = 49.27 cm²The calculator must be in radian mode: sin 1.4 = 0.985, not 0.0244.[1]
  4. Segment = 70 − 49.27 = 20.7 cm²Segment is sector minus triangle; rounded to 3 s.f.[1]

20.7 cm²

Exam questions

1 · 6 marks

Multi-part questions with a full mark scheme.

Q1[6 marks]
The diagram shows a sector OAB of a circle centre O with radius 9 cm, where angle AOB = θ radians. The perimeter of the sector is 33 cm.
(a) Find θ.
(b) Hence find the area of the sector.
(c) Find the area of the triangle OAB, and state what the difference between your answers to (b) and (c) represents.
Mark scheme
  1. (a) Perimeter = rθ + 2r, so 9θ + 18 = 33Setting up the perimeter correctly is the step being tested.[1]
  2. 9θ = 15, so θ = 5/3 ≈ 1.67 radLeave it exact where possible; the fraction is cleaner for part (b).[1]
  3. (b) A = ½r²θ = ½ × 81 × 5/3Substituting the exact value avoids rounding error carrying forward.[1]
  4. = 67.5 cm²Exact, because 81 × 5 / 6 divides cleanly.[1]
  5. (c) Triangle = ½r² sin θ = ½ × 81 × sin(5/3) = 40.5 × 0.99575 = 40.3 cm²Radian mode again; sin(5/3 rad) is close to 1 because 5/3 rad is near 95°.[1]
  6. Difference = 67.5 − 40.3 = 27.2 cm², which is the area of the segment cut off by chord AB.The final mark is for naming the region, not for the subtraction.[1]

θ = 5/3 rad; sector 67.5 cm²; triangle 40.3 cm²; difference 27.2 cm² is the segment